Can lambda functions be templated?

Question

In C++11, is there a way to template a lambda function? Or is it inherently too specific to be templated?

I understand that I can define a classic templated class/fu

Answer 1

C++11 lambdas can't be templated as stated in other answers but decltype() seems to help when using a lambda within a templated class or function.

#include 
#include 

using namespace std;

template
void boring_template_fn(T t){
    auto identity = [](decltype(t) t){ return t;};
    std::cout << identity(t) << std::endl;
}

int main(int argc, char *argv[]) {
    std::string s("My string");
    boring_template_fn(s);
    boring_template_fn(1024);
    boring_template_fn(true);
}

Prints:

My string
1024
1

I've found this technique is helps when working with templated code but realize it still means lambdas themselves can't be templated.