Let\'s say you wanted to implement a breadth-first search of a binary tree recursively. How would you go about it?
Is it possible using only the call-stack
C# implementation of recursive breadth-first search algorithm for a binary tree.
Binary tree data visualization
IDictionary graph = new Dictionary {
{"A", new [] {"B", "C"}},
{"B", new [] {"D", "E"}},
{"C", new [] {"F", "G"}},
{"E", new [] {"H"}}
};
void Main()
{
var pathFound = BreadthFirstSearch("A", "H", new string[0]);
Console.WriteLine(pathFound); // [A, B, E, H]
var pathNotFound = BreadthFirstSearch("A", "Z", new string[0]);
Console.WriteLine(pathNotFound); // []
}
IEnumerable BreadthFirstSearch(string start, string end, IEnumerable path)
{
if (start == end)
{
return path.Concat(new[] { end });
}
if (!graph.ContainsKey(start)) { return new string[0]; }
return graph[start].SelectMany(letter => BreadthFirstSearch(letter, end, path.Concat(new[] { start })));
}
If you want algorithm to work not only with binary-tree but with graphs what can have two and more nodes that points to same another node you must to avoid self-cycling by holding list of already visited nodes. Implementation may be looks like this.
Graph data visualization
IDictionary graph = new Dictionary {
{"A", new [] {"B", "C"}},
{"B", new [] {"D", "E"}},
{"C", new [] {"F", "G", "E"}},
{"E", new [] {"H"}}
};
void Main()
{
var pathFound = BreadthFirstSearch("A", "H", new string[0], new List());
Console.WriteLine(pathFound); // [A, B, E, H]
var pathNotFound = BreadthFirstSearch("A", "Z", new string[0], new List());
Console.WriteLine(pathNotFound); // []
}
IEnumerable BreadthFirstSearch(string start, string end, IEnumerable path, IList visited)
{
if (start == end)
{
return path.Concat(new[] { end });
}
if (!graph.ContainsKey(start)) { return new string[0]; }
return graph[start].Aggregate(new string[0], (acc, letter) =>
{
if (visited.Contains(letter))
{
return acc;
}
visited.Add(letter);
var result = BreadthFirstSearch(letter, end, path.Concat(new[] { start }), visited);
return acc.Concat(result).ToArray();
});
}