Why is there no xrange function in Python3?

Question

Recently I started using Python3 and it\'s lack of xrange hurts.

Simple example:

1) Python2:

from time import time as t
def          


        

Answer 1

comp:~$ python Python 2.7.6 (default, Jun 22 2015, 17:58:13) [GCC 4.8.2] on linux2

>>> import timeit
>>> timeit.timeit("[x for x in xrange(1000000) if x%4]",number=100)

5.656799077987671

>>> timeit.timeit("[x for x in xrange(1000000) if x%4]",number=100)

5.579368829727173

>>> timeit.timeit("[x for x in range(1000000) if x%4]",number=100)

21.54827117919922

>>> timeit.timeit("[x for x in range(1000000) if x%4]",number=100)

22.014557123184204

With timeit number=1 param:

>>> timeit.timeit("[x for x in range(1000000) if x%4]",number=1)

0.2245171070098877

>>> timeit.timeit("[x for x in xrange(1000000) if x%4]",number=1)

0.10750913619995117

comp:~$ python3 Python 3.4.3 (default, Oct 14 2015, 20:28:29) [GCC 4.8.4] on linux

>>> timeit.timeit("[x for x in range(1000000) if x%4]",number=100)

9.113872020003328

>>> timeit.timeit("[x for x in range(1000000) if x%4]",number=100)

9.07014398300089

With timeit number=1,2,3,4 param works quick and in linear way:

>>> timeit.timeit("[x for x in range(1000000) if x%4]",number=1)

0.09329321900440846

>>> timeit.timeit("[x for x in range(1000000) if x%4]",number=2)

0.18501482300052885

>>> timeit.timeit("[x for x in range(1000000) if x%4]",number=3)

0.2703447980020428

>>> timeit.timeit("[x for x in range(1000000) if x%4]",number=4)

0.36209142999723554

So it seems if we measure 1 running loop cycle like timeit.timeit("[x for x in range(1000000) if x%4]",number=1) (as we actually use in real code) python3 works quick enough, but in repeated loops python 2 xrange() wins in speed against range() from python 3.