Equivalent of *Nix 'which' command in PowerShell?

Question

How do I ask PowerShell where something is?

For instance, \"which notepad\" and it returns the directory where the notepad.exe is run from according to the current

Answer 1

I have this which advanced function in my PowerShell profile:

function which {
<#
.SYNOPSIS
Identifies the source of a PowerShell command.
.DESCRIPTION
Identifies the source of a PowerShell command. External commands (Applications) are identified by the path to the executable
(which must be in the system PATH); cmdlets and functions are identified as such and the name of the module they are defined in
provided; aliases are expanded and the source of the alias definition is returned.
.INPUTS
No inputs; you cannot pipe data to this function.
.OUTPUTS
.PARAMETER Name
The name of the command to be identified.
.EXAMPLE
PS C:\Users\Smith\Documents> which Get-Command

Get-Command: Cmdlet in module Microsoft.PowerShell.Core

(Identifies type and source of command)
.EXAMPLE
PS C:\Users\Smith\Documents> which notepad

C:\WINDOWS\SYSTEM32\notepad.exe

(Indicates the full path of the executable)
#>
    param(
    [String]$name
    )

    $cmd = Get-Command $name
    $redirect = $null
    switch ($cmd.CommandType) {
        "Alias"          { "{0}: Alias for ({1})" -f $cmd.Name, (. { which cmd.Definition } ) }
        "Application"    { $cmd.Source }
        "Cmdlet"         { "{0}: {1} {2}" -f $cmd.Name, $cmd.CommandType, (. { if ($cmd.Source.Length) { "in module {0}" -f $cmd.Source} else { "from unspecified source" } } ) }
        "Function"       { "{0}: {1} {2}" -f $cmd.Name, $cmd.CommandType, (. { if ($cmd.Source.Length) { "in module {0}" -f $cmd.Source} else { "from unspecified source" } } ) }
        "Workflow"       { "{0}: {1} {2}" -f $cmd.Name, $cmd.CommandType, (. { if ($cmd.Source.Length) { "in module {0}" -f $cmd.Source} else { "from unspecified source" } } ) }
        "ExternalScript" { $cmd.Source }
        default          { $cmd }
    }
}