Type conversion warning after bitwise operations in C

Question

How do you explain that line 7 gets a warning, but not line 5 or line 6?

int main()
{
    unsigned char a = 0xFF;
    unsig         


        

Answer 1

The return type of bitwise operator & is integer. Whenever you cast an int (4 bytes) into char or unsigned char (1 byte) it gives you warning.

So this is not related to bitwise operator it is related to typecasting from 4 bytes variable to 1 bytes variable.