Extract filename and extension in Bash

Question

I want to get the filename (without extension) and the extension separately.

The best solution I found so far is:

NAME=`echo \"$FILE\" | cut -d\'.\'          


        

Answer 1

A simple answer:

To expand on the POSIX variables answer, note that you can do more interesting patterns. So for the case detailed here, you could simply do this:

tar -zxvf $1
cd ${1%.tar.*}

That will cut off the last occurrence of .tar..

More generally, if you wanted to remove the last occurrence of .. then

${1.*.*}

should work fine.

The link the above answer appears to be dead. Here's a great explanation of a bunch of the string manipulation you can do directly in Bash, from TLDP.