Extract filename and extension in Bash

Question

I want to get the filename (without extension) and the extension separately.

The best solution I found so far is:

NAME=`echo \"$FILE\" | cut -d\'.\'          


        

Answer 1

You could use the cut command to remove the last two extensions (the ".tar.gz" part):

$ echo "foo.tar.gz" | cut -d'.' --complement -f2-
foo

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As noted by Clayton Hughes in a comment, this will not work for the actual example in the question. So as an alternative I propose using sed with extended regular expressions, like this:

$ echo "mpc-1.0.1.tar.gz" | sed -r 's/\.[[:alnum:]]+\.[[:alnum:]]+$//'
mpc-1.0.1

It works by removing the last two (alpha-numeric) extensions unconditionally.

[Updated again after comment from Anders Lindahl]