How to debug child Node.JS process in Visual Studio Code?

Question

How to debug child Node.JS process in VS Code?
Here is the example of the code that I\'m trying to debug:

var spawn = require(\'child_process\').spawn;
var s         


        

Answer 1

Look for this npm module child-process-debug.

I created 2 separate launch configurations in vscode:

One for master process, other for child process

   {
        "name": "Attach",
        "type": "node",
        "request": "attach",
        "port": 5858,
        "address": "localhost",
        "restart": false,
        "sourceMaps": false,
        "outFiles": [],
        "localRoot": "${workspaceRoot}",
        "remoteRoot": null
    },
    {
        "name": "Attach child",
        "type": "node",
        "request": "attach",
        "port": 5859,
        "address": "localhost",
        "restart": false,
        "sourceMaps": false,
        "outFiles": [],
        "localRoot": "${workspaceRoot}",
        "remoteRoot": null
    }

Workflow as follows:

1. Start master node process with --debug command line switch $ node --debug master.js
2. Attach to master.js node process using Attach via debug panel
3. Place break point in the child.js process
4. Quickly detach from main process and attach to child process using Attach child

Fro debugging purposes, you may delay message sending between processes using setTimeout

// master.js
var child = child_process.fork(__dirname + './child.js')
setTimeout(function() {
    child.send('...')
}, 5000)