Date arithmetic in Unix shell scripts

Question

I need to do date arithmetic in Unix shell scripts that I use to control the execution of third party programs.

I\'m using a function to increment a day and another

Answer 1

Looking into it further, I think you can simply use date. I've tried the following on OpenBSD: I took the date of Feb. 29th 2008 and a random hour (in the form of 080229301535) and added +1 to the day part, like so:

$ date -j 0802301535
Sat Mar  1 15:35:00 EST 2008

As you can see, date formatted the time correctly...

HTH