How to use switch-case on a Type? [duplicate]

Answer 1

You cannot use a switch block to test values of type Type. Compiling your code should give you an error saying something like:

A switch expression or case label must be a bool, char, string, integral, enum, or corresponding nullable type

You'll need to use if-else statements instead.

Also: typeof(int) and typeof(Int32) are equivalent. int is a keyword and Int32 is the type name.

UPDATE

If you expect that most types will be intrinsic you may improve performance by using a switch block with Type.GetTypeCode(...).

For example:

switch (Type.GetTypeCode(type))
{
    case TypeCode.Int32:
        // It's an int
        break;

    case TypeCode.String:
        // It's a string
        break;

    // Other type code cases here...

    default:
        // Fallback to using if-else statements...
        if (type == typeof(MyCoolType))
        {
            // ...
        }
        else if (type == typeof(MyOtherType))
        {
            // ...
        } // etc...
}