How can I position the window's position on startup to the right side of the user's screen?

Question

I am currently creating a sidebar-like WPF application in C#. When a user starts the application, I would like the window to automatically position it\'s self to the side of the

Answer 1

Description

You can use Screen from System.Windows.Forms.

So add reference to the System.Windows.Forms.dll and System.Drawing.dll. Then change the Left and Height property in the MainWindow_Loaded method.

Sample

public MainWindow()
{
    InitializeComponent();
    this.Loaded += new RoutedEventHandler(MainWindow_Loaded);
}

void MainWindow_Loaded(object sender, RoutedEventArgs e)
{
    this.Left = System.Windows.Forms.Screen.PrimaryScreen.WorkingArea.Right - this.Width;
    this.Top = 0;
    this.Height = System.Windows.Forms.Screen.PrimaryScreen.WorkingArea.Height;
}

More Information

• MSDN - Screen Class