I am trying to display an image coming from the database and I was not able to display the image .but its showing like this user-1.jpg Please see my code can on
user-1.jpg
$sqlimage = "SELECT image FROM userdetail where `id` = $id1"; $imageresult1 = mysqli_query($link, $sqlimage); while($rows=mysqli_fetch_assoc($imageresult1)) { echo "'; }