how to convert std::vector to void*

Question

I am wondering how can I convert std::vector to void*, for example:

std::vector pixels_ (w*h, background_         


        

Answer 1

To transform your vector into a void* type, there are two options:

• Pre C++11: (void*)&pixels_[0] (!empty() check is recommended)
• Since C++11: static_cast(pixels_.data())

However, if you want to copy the elements, go straight with STL functions:

• std::copy
• std::uninitialized_copy

They are type safe, your code looks much cleaner and the performance will be on par most of the times. Also, unlike std::memcpy, it also supports non-trivially copyable types (for example std::shared_ptr).

Remember:

We should forget about small efficiencies, say about 97% of the time: premature optimization is the root of all evil. Yet we should not pass up our opportunities in that critical 3%

See TriviallyCopyable

Update: since C++17 you can also use std::data, which will work for any container using contiguous memory storage (e.g. std::vector, std::string, std::array).

ColorData* buffer = std::data(pixels_);