Python closure function losing outer variable access

Question

I just learned python @ decorator, it\'s cool, but soon I found my modified code coming out weird problems.

def with_wrapper(param1):
    def dummy_wrapper(fn):
         


        

Answer 1

You assign param1 in the function, which makes param1 a local variable. However, it hasn't been assigned at the point you're printing it, so you get an error. Python doesn't fall back to looking for variables in outer scopes.