Get actual type of generic type argument on abstract superclass

Question

I have a class like:

public abstract class BaseDao {

  protected Class getClazz() {
     return T.class;
  }

  /         


        

Answer 1

If your class is abstract, you can try with this:

public class getClassOfT() {
    final ParameterizedType type = (ParameterizedType) this.getClass()
            .getGenericSuperclass();
    Class clazz = (Class) type.getActualTypeArguments()[0];
    return clazz;
}

This only work if the instance is a direct subclass, and the type of the class you want is the first one (see the [0]).

If you have a large hierarchy of dao's, you can try fidn the BaseDao recursively and get the parametrized type

See a example here (see the output in the bottom)

Cheers and sorry for my bad english