I have a vector variable. I need to pass it onto a method which accepts char**as an input parameter.
how to do this ? If
It is possible to solve the problem without copying out all the std::strings as long as the function does not modify the passed in char**. Otherwise I can see no alternative but to copy out everything into a new char**` structure (see second example).
void old_func(char** carray, size_t size)
{
for(size_t i = 0; i < size; ++i)
std::cout << carray[i] << '\n';
}
int main()
{
std::vector strings {"one", "two", "three"};
std::vector cstrings;
cstrings.reserve(strings.size());
for(size_t i = 0; i < strings.size(); ++i)
cstrings.push_back(const_cast(strings[i].c_str()));
// Do not change any of the strings here as that will
// invalidate the new data structure that relies on
// the returned values from `c_str()`
//
// This is not an issue after C++11 as long as you don't
// increase the length of a string (as that may cause reallocation)
if(!cstrings.empty())
old_func(&cstrings[0], cstrings.size());
}
EXAMPLE 2: If the function must modify the passed in data:
void old_func(char** carray, size_t size)
{
for(size_t i = 0; i < size; ++i)
std::cout << carray[i] << '\n';
}
int main()
{
{
// pre C++11
std::vector strings {"one", "two", "three"};
// guarantee contiguous, null terminated strings
std::vector> vstrings;
// pointers to rhose strings
std::vector cstrings;
vstrings.reserve(strings.size());
cstrings.reserve(strings.size());
for(size_t i = 0; i < strings.size(); ++i)
{
vstrings.emplace_back(strings[i].begin(), strings[i].end());
vstrings.back().push_back('\0');
cstrings.push_back(vstrings.back().data());
}
old_func(cstrings.data(), cstrings.size());
}
{
// post C++11
std::vector strings {"one", "two", "three"};
std::vector cstrings;
cstrings.reserve(strings.size());
for(auto& s: strings)
cstrings.push_back(&s[0]);
old_func(cstrings.data(), cstrings.size());
}
}
NOTE: Revised to provide better code.