How to convert an integer to hexadecimal without the extra '0x' leading and 'L' trailing characters in Python?

Question

I am trying to convert big integer number to hexadecimal, but in result I get extra \"0x\" in the beginning and \"L\" at the and. Is there any way to remove them. Thanks. The nu

Answer 1

I think it's dangerous idea to use strip.
because lstrip or rstrip strips 0.

ex)

a = '0x0'
a.lstrip('0x')  

''

result is '', not '0'.

In your case, you can simply use replce to prevent above situation.
Here's sample code.

hex(bignum).replace("L","").replace("0x","")