I am working on a project where at one point I am stuck.
My question is for example I have the following 2D array containing 3 different integers.
2 2 2
I love this kind of problems :-) so here it is my answer.
As said by Frerich Raabe, this can be solved with a floodFill function. For example, opencv
library would provide such a function off the shelf.
Please forgive me if in the following code you'll find traces of C++, in case they should be simple to be replaced.
typedef struct Point {
int x;
int y;
} Point;
int areaOfBiggestContiguousRegion(int* mat,int nRows, int nCols) {
int maxArea = 0;
int currValue, queueSize, queueIndex;
int* aux;
Point queue[1000]; //Stores the points I need to label
Point newPoint, currentPoint;
int x,y,x2,y2;
//Code: allocate support array aux of same size of mat
//Code: fill aux of zeros
for (y = 0; y < nRows; y++)
for (x = 0; x < nCols; x++)
if (aux[y * nCols + x] == 0) {//I find a pixel not yet labeled, my seed for the next flood fill
queueIndex = 0; //Contains the index to the next element in the queue
queueSize = 0;
currValue = mat[y * nCols + x]; //The "color" of the current spot
aux[y * nCols + x] = 1;
newPoint.x = x;
newPoint.y = y;
queue[queueSize] = newPoint;
queueSize++;
while(queueIndex != queueSize) {
currPoint = queue[queueIndex];
queueIndex++;
//Look left, right, up, down
x2 = currPoint.x - 1;
y2 = currPoint.y;
//Some copy & paste, sorry I have been too long on C++ to remember correctly about C functions
if (x2 >= 0 && aux[y2 * nCols + x2] == 0 && mat[y2 * nCols + x2] == currValue) {
aux[y2 * nCols + x2] = 1;
newPoint.x = x2;
newPoint.y = y2;
queue[queueSize] = newPoint;
queueSize++;
}
x2 = currPoint.x + 1;
y2 = currPoint.y;
//Some copy & paste, sorry I have been too long on C++ to remember correctly about C functions
if (x2 < nCols && aux[y2 * nCols + x2] == 0 && mat[y2 * nCols + x2] == currValue) {
aux[y2 * nCols + x2] = 1;
newPoint.x = x2;
newPoint.y = y2;
queue[queueSize] = newPoint;
queueSize++;
}
x2 = currPoint.x;
y2 = currPoint.y - 1;
//Some copy & paste, sorry I have been too long on C++ to remember correctly about C functions
if (y2 >= 0 && aux[y2 * nCols + x2] == 0 && mat[y2 * nCols + x2] == currValue) {
aux[y2 * nCols + x2] = 1;
newPoint.x = x2;
newPoint.y = y2;
queue[queueSize] = newPoint;
queueSize++;
}
x2 = currPoint.x;
y2 = currPoint.y + 1;
//Some copy & paste, sorry I have been too long on C++ to remember correctly about C functions
if (y2 < nRows && aux[y2 * nCols + x2] == 0 && mat[y2 * nCols + x2] == currValue) {
aux[y2 * nCols + x2] = 1;
newPoint.x = x2;
newPoint.y = y2;
queue[queueSize] = newPoint;
queueSize++;
}
} //while
if (queueSize > maxArea)
maxArea = queueSize; //If necessary we could store other details like currentValue
}//if (aux...
return maxArea;
}
Note: In C++ using std containers and a constructor for Point
it becomes much more compact