Python regex to match punctuation at end of string

Question

I need to match if a sentence starts with a capital and ends with [?.!] in Python.

EDIT It must have [?.!] only at end but allo

Answer 1

I made it working for myself, and just for clarification or if other people have the same problem this is what did the trick for me:

re.match('^[A-Z][^?!.]*[?.!]$', sentence) is not None

Explanation: Where ^[A-Z] looks for a Capital at start

'[^?!.]*' means everything in between start and end is ok except things containing ? or ! or .

[?.!]$ must end with ? or ! or .