How to create an array when the size is a variable not a constant?

Question

I\'ve got a method that receives a variable int. That variable constitutes an array size (please, don\'t offer me a vector). Thus, I need to init a const int inside my metho

Answer 1

C++ does not support variable-length arrays. Instead, you'll need to allocate the array dynamically:

std::vector a(variable_int);

or since you say you don't want to use a vector for some reason:

class not_a_vector
{
public:
    explicit not_a_vector(size_t size) : a(new int[size]()) {}
    ~not_a_vector() {delete [] a;}
    int & operator[](size_t i) {return a[i];}
    int   operator[](size_t i) const {return a[i];}

    not_a_vector(not_a_vector const &) = delete;
    void operator=(not_a_vector const &) = delete;

private:
    int * a;
};

not_a_vector a(variable_int);

UPDATE: The question has just been updated with the "C" tag as well as "C++". C (since 1999) does support variable-length arrays, so your code should be fine in that language.