Is it possible to prevent multiple inheritance of specific base classes at compile time?

Question

What I am looking to do is develop two different base classes which should not be inherited together in the one derived class. Is there any way I can enforce this at compile tim

Answer 1

An interesting problem. I found a solution that works for Microsoft (R) C/C++ Optimizing Compiler Version 18.00.31101 for x64:

#include 
#include 
using namespace std;

class SuperBase {
public:
SuperBase():count(0) {
    cout << "SuperBase constructor..." << endl;
}
~SuperBase() {}
protected:
int count;
};
class Base1:virtual SuperBase
{
public:
Base1() 
{
    SuperBase::count++;
    assert(SuperBase::count==1);
    cout << "Base1 constructor..." << endl;
}

~Base1() 
{
    cout << "Base1 Destructor..." << endl;
}
};  

class Base2:virtual SuperBase
{
public:
Base2() 
{
    SuperBase::count++;
    assert(SuperBase::count==1);
    cout << "Base2 constructor..." << endl;
}

~Base2() 
{
  cout << "Base2 Destructor..." << endl;  
}
};

class Derived : public Base1, public Base2 
{
public:
  Derived()
  {
  cout << "Derived constructor...."  << endl;
  }
  ~Derived()
  {
  cout << "Derived Destructor..." << endl;
   }
};

class Derived1 : public Base1
{
public:
  Derived1()
  {
  cout << "Derived1 constructor...."  << endl;
  }
  ~Derived1()
  {
  cout << "Derived1 Destructor..." << endl;
   }
};
class Derived2 : public Base2
{
public:
  Derived2()
  {
  cout << "Derived2 constructor...."  << endl;
  }
  ~Derived2()
  {
  cout << "Derived2 Destructor..." << endl;
   }
};



int main()
{
   cout << "Hello World" << endl; 
   Base1 b1; Base2 b2;
   Derived1 d1; 
   Derived2 d2;
   // Derived d; // - uncomment this line to get run-time error.

   return 0;
}