How to deserialize an object with PyYAML using safe_load?

Question

Having a snippet like this:

import yaml
class User(object):
    def __init__(self, name, surname):
       self.name= name
       self.surname= surname

user = U         


        

Answer 1

Another way exists. From the PyYaml docs:

A python object can be marked as safe and thus be recognized by yaml.safe_load. To do this, derive it from yaml.YAMLObject [...] and explicitly set its class property yaml_loader to yaml.SafeLoader.

You also have to set the yaml_tag property to make it work.

YAMLObject does some metaclass magic to make the object loadable. Note that if you do this, the objects will only be loadable by the safe loader, not with regular yaml.load().

Working example:

import yaml

class User(yaml.YAMLObject):
    yaml_loader = yaml.SafeLoader
    yaml_tag = u'!User'

    def __init__(self, name, surname):
       self.name= name
       self.surname= surname

user = User('spam', 'eggs')
serialized_user = yaml.dump(user)

#Network

deserialized_user = yaml.safe_load(serialized_user)
print "name: %s, sname: %s" % (deserialized_user.name, deserialized_user.surname)

The advantage of this one is that it's prety easy to do; the disadvantages are that it only works with safe_load and clutters your class with serialization-related attributes and metaclass.