Nullable reference types with generic return type

Question

I\'m playing around a bit with the new C# 8 nullable reference types feature, and while refactoring my code I came upon this (simplified) method:

public T Get         


        

Answer 1

In C# 9 you are able to express nullability of unconstrained generics more naturally:

public T? Get(string key)
{
    var wrapper = cacheService.Get(key);
    return wrapper.HasValue ? Deserialize(wrapper) : default;
}

Note there's no ! operator on the default expression. The only change from your original example is the addition of ? to the T return type.