return string with first match Regex

Question

I want to get the first match of a regex.

In this case, I got a list:

text = \'aa33bbb44\'
re.findall(\'\\d+\',text)

Answer 1

Maybe this would perform a bit better in case greater amount of input data does not contain your wanted piece because except has greater cost.

def return_first_match(text):
    result = re.findall('\d+',text)
    result = result[0] if result else ""
    return result