return string with first match Regex

Question

I want to get the first match of a regex.

In this case, I got a list:

text = \'aa33bbb44\'
re.findall(\'\\d+\',text)

Answer 1

You can do:

x = re.findall('\d+', text)
result = x[0] if len(x) > 0 else ''

Note that your question isn't exactly related to regex. Rather, how do you safely find an element from an array, if it has none.