return string with first match Regex

Question

I want to get the first match of a regex.

In this case, I got a list:

text = \'aa33bbb44\'
re.findall(\'\\d+\',text)

Answer 1

I'd go with:

r = re.search("\d+", ch)
result = return r.group(0) if r else ""

re.search only looks for the first match in the string anyway, so I think it makes your intent slightly more clear than using findall.