Skip iterations in enumerated list object (python)

Question

I have the code

for iline, line in enumerate(lines):
    ...
    if :
        

I would like, as you c

Answer 1

Using the enumeration index

Similar to the accepted answer… except without using itertools (IMHO islice doesn't improve readability), plus enumerate() already returns an iterator so you don't need the iter() at all:

lines = [{str(x): x} for x in range(20)]  # dummy data

it = enumerate(lines)
for i, line in it:
    print(line)

    if i == 10:  # condition using enumeration index
        [next(it, None) for _ in range(5)]  # skip 5

That last line can optionally be expanded for readability:

        for _ in range(5):  # skip 5
            next(it, None)

The None argument in next() avoids an exception if there aren't enough items to skip. (For the original question, it can be omitted as the OP wrote: "I can be sure that, if the condition is met, there are 5 or more objects left in the lines object.")

Not using the enumeration index

If the skip condition isn't based on the enumeration index, simply treat the list as a FIFO queue and consume from it using pop():

lines = [{str(x): x} for x in range(20)]  # dummy data

while lines:
    line = lines.pop(0)  # get first item
    print(line)

    if :  # some other kind of condition
        [lines.pop(0) for _ in range(5)]  # skip 5

As before, that last line can optionally be expanded for readability:

        for _ in range(5):  # skip 5
            lines.pop(0)

(For large lists, use collections.deque for performance.)