How to print lines between two patterns, inclusive or exclusive (in sed, AWK or Perl)?

Question

I have a file like the following and I would like to print the lines between two given patterns PAT1 and PAT2.

Answer 1

What about the classic sed solution?

Print lines between PAT1 and PAT2 - include PAT1 and PAT2

sed -n '/PAT1/,/PAT2/p' FILE

Print lines between PAT1 and PAT2 - exclude PAT1 and PAT2

GNU sed

sed -n '/PAT1/,/PAT2/{/PAT1/!{/PAT2/!p}}' FILE

Any sed¹

sed -n '/PAT1/,/PAT2/{/PAT1/!{/PAT2/!p;};}' FILE

or even (Thanks Sundeep):

GNU sed

sed -n '/PAT1/,/PAT2/{//!p}' FILE

Any sed

sed -n '/PAT1/,/PAT2/{//!p;}' FILE

Print lines between PAT1 and PAT2 - include PAT1 but not PAT2

The following includes just the range start:

GNU sed

sed -n '/PAT1/,/PAT2/{/PAT2/!p}' FILE

Any sed

sed -n '/PAT1/,/PAT2/{/PAT2/!p;}' FILE

Print lines between PAT1 and PAT2 - include PAT2 but not PAT1

The following includes just the range end:

GNU sed

sed -n '/PAT1/,/PAT2/{/PAT1/!p}' FILE

Any sed

sed -n '/PAT1/,/PAT2/{/PAT1/!p;}' FILE

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¹ Note about BSD/Mac OS X sed

A command like this here:

sed -n '/PAT1/,/PAT2/{/PAT1/!{/PAT2/!p}}' FILE

Would emit an error:

▶ sed -n '/PAT1/,/PAT2/{/PAT1/!{/PAT2/!p}}' FILE
sed: 1: "/PAT1/,/PAT2/{/PAT1/!{/ ...": extra characters at the end of p command

For this reason this answer has been edited to include BSD and GNU versions of the one-liners.