Change bits value in Byte

Question

I have some data in field type Byte ( I save eight inputs in Byte, every bit is one input ). How to change just one input in that field ( Byte) but not to lose information about

Answer 1

To set the seventh bit to 1:

b = (byte) (b | (1 << 6));

To set the sixth bit to zero:

b = (byte) (b & ~(1 << 5));

(The bit positions are effectively 0-based, so that's why the "seventh bit" maps to 1 << 6 instead of 1 << 7.)