Uploading Multiple Files to Google Drive with Google App Script

Question

I\'m trying to upload multiple files at once with my app. It recognizes when there are 2 or more files being selected. However, it will only upload the 1st file that is sele

Answer 1

You have to send a file at a time trough the script.run, here's my implementation with FileReaders/ReadAsURL, which makes the file a Base64 string, which can be easily passed around:

Notes:

1. Dunno if it's necessary but I'm using IFRAME sandbox
2. I left the progressBar in the code, you can remove it
3. Everything must be OUTSIDE a form
4. It accepts any file type

HTML:

// Upload de arquivo dentro das pastas Arquivos Auxiliares
function iterarArquivosUpload() {
    var arquivos = document.getElementById('inputUpload').files;

    if (arquivos.length == 0) {
        alert('No file selected!');
    } else {
        //Show Progress Bar
        numUploads.total = arquivos.length;
        $('.progressUpload').progressbar({
            value : false
        });
        $('.labelProgressUpload').html('Preparando arquivos para upload');

        // Send each file at a time
        for (var arqs = 0; arqs < numUploads.total; arqs++) {
            console.log(arqs);
            enviarArquivoParaDrive(arquivos[arqs]);
        }
    }
}

function enviarArquivoParaDrive(arquivo) {
    var reader = new FileReader();
    reader.onload = function (e) {
        var content = reader.result;
        console.log('Sending ' + arquivo.name);
        google.script.run.withSuccessHandler(updateProgressbar).uploadArquivoParaDrive(content, arquivo.name, currFolder);
    }
    reader.readAsDataURL(arquivo);
}

function updateProgressbar( idUpdate ){
   console.log('Received: ' + idUpdate);
   numUploads.done++;
   var porc = Math.ceil((numUploads.done / numUploads.total)*100);
   $('.progressUpload').progressbar({value: porc });
   $('.labelProgressUpload').html(numUploads.done +'/'+ numUploads.total);
   if( numUploads.done == numUploads.total ){
      uploadsFinished();
      numUploads.done = 0;
   };
}

Code.GS

function uploadArquivoParaDrive(base64Data, nomeArq, idPasta) {
  try{
    var splitBase = base64Data.split(','),
        type = splitBase[0].split(';')[0].replace('data:','');

    var byteCharacters = Utilities.base64Decode(splitBase[1]);
    var ss = Utilities.newBlob(byteCharacters, type);
    ss.setName(nomeArq);

    var file = DriveApp.getFolderById(idPasta).createFile(ss);

    return file.getName();
  }catch(e){
    return 'Erro: ' + e.toString();
  }
}