Store an int in a char array?

Question

I want to store a 4-byte int in a char array... such that the first 4 locations of the char array are the 4 bytes of the int.

Then, I want to pull the int back out o

Answer 1

char a[10];
int i=9;

a=boost::lexical_cast(i)

found this is the best way to convert char into int and vice-versa.

alternative to boost::lexical_cast is sprintf.

char temp[5];
temp[0]="h"
temp[1]="e"
temp[2]="l"
temp[3]="l"
temp[5]='\0'
sprintf(temp+4,%d",9)
cout<

output would be :hell9