Using typeid to get name of derived class

Question

I\'m creating a resource manager that takes in classes derived from the class Resource. My problem is that typeid(..).name() returns the wrong name of the class.

Answer 1

My problem is that typeid(..).name() returns the wrong name of the class.

typeid(...).name() is only useful for debugging or logging purposes. As http://en.cppreference.com/w/cpp/types/type_info/name says:

No guarantees are given, in particular, the returned string can be identical for several types and change between invocations of the same program.

As for your problem,

How can I make the first typeid statement yield 'Texture' without using type conversions?

The safest, easiest and most correct way to do this would be to add a virtual name function of your own to Resource:

virtual std::string name() const = 0;

Then override it in every subclass to return the name of the class.