How to convert a double into a byte array in swift?

Question

I know how to do it in java (see here), but I couldn\'t find a swift equivalent for java\'s ByteBuffer, and consequently its .putDouble(double value) method.

Basically,

Answer 1

typealias Byte = UInt8

func toByteArray(var value: T) -> [Byte] {
    return withUnsafePointer(&value) {
        Array(UnsafeBufferPointer(start: UnsafePointer($0), count: sizeof(T)))
    }
}

toByteArray(1729.1729)
toByteArray(1729.1729 as Float)
toByteArray(1729)
toByteArray(-1729)

But the results are reversed from your expectations (because of endianness):

[234, 149, 178, 12, 177, 4, 155, 64]
[136, 37, 216, 68]
[193, 6, 0, 0, 0, 0, 0, 0]
[63, 249, 255, 255, 255, 255, 255, 255]

---

Added:

func fromByteArray(value: [Byte], _: T.Type) -> T {
    return value.withUnsafeBufferPointer {
        return UnsafePointer($0.baseAddress).memory
    }
}

let a: Double = 1729.1729
let b = toByteArray(a) // -> [234, 149, 178, 12, 177, 4, 155, 64]
let c = fromByteArray(b, Double.self) // -> 1729.1729

---

For Xcode8/Swift3.0:

func toByteArray(_ value: T) -> [UInt8] {
    var value = value
    return withUnsafePointer(to: &value) {
        $0.withMemoryRebound(to: UInt8.self, capacity: MemoryLayout.size) {
            Array(UnsafeBufferPointer(start: $0, count: MemoryLayout.size))
        }
    }
}

func fromByteArray(_ value: [UInt8], _: T.Type) -> T {
    return value.withUnsafeBufferPointer {
        $0.baseAddress!.withMemoryRebound(to: T.self, capacity: 1) {
            $0.pointee
        }
    }
}

---

For Xcode8.1/Swift3.0.1

func toByteArray(_ value: T) -> [UInt8] {
    var value = value
    return withUnsafeBytes(of: &value) { Array($0) }
}

func fromByteArray(_ value: [UInt8], _: T.Type) -> T {
    return value.withUnsafeBytes {
        $0.baseAddress!.load(as: T.self)
    }
}