Why is there no strtoi in stdlib.h?

Question

I have grown accustomed to strtod and variants. I am wondering why there is no strtoi shipped with stdlib.h. Why is it that the integer is left out of this part

Answer 1

Why is there no strtoi in stdlib.h?

No critical need.

In early C, there was not a standard signed type wider than long and all narrower conversions, like int, could be made from strtol() - as done below.

IMO, these and their unsigned counterparts are now missing C functions and a design shortcoming in the current standard C library (C17/18).

---

On many systems, long and int have the same range and so there is a reduced need for a separate strtoi(). Also the atoi() fills the need for quick and dirty code, but can lack error detection. There also is not a strto_short() nor strto_signchar(), etc.

It is fairly easy to create a substitute strtoi(). Simplifications exist.

#include 
#include 
#include 

static long strto_subrange(const char *s, char **endptr, int base, 
    long min, long max) {
  long y = strtol(s, endptr, base);
  if (y > max) {
    errno = ERANGE;
    return max;
  }
  if (y < min) {
    errno = ERANGE;
    return min;
  }
  return y;
}

// OP's goal
int strtoi(const char *s, char **endptr, int base) {
  #if INT_MAX == LONG_MAX && INT_MIN == LONG_MIN
    return (int) strtol(s, endptr, base);
  #else
    return (int) strto_subrange(s, endptr, base, INT_MIN, INT_MAX);
  #endif
}

short strtoshort(const char *s, char **endptr, int base) {
  return (short) strto_subrange(s, endptr, base, SHRT_MIN, SHRT_MAX);
}

signed char strtoschar(const char *s, char **endptr, int base) {
  return (signed char) strto_subrange(s, endptr, base, SCHAR_MIN, SCHAR_MAX);
}

#include 
int16_t strtoint16(const char *s, char **endptr, int base) {
  return (int16_t) strto_subrange(s, endptr, base, INT16_MIN, INT16_MAX);
}