Is there a better way of merging overlapping date intervals?
The solution I came up with is so simple that now I wonder if someone else has a better idea of how this cou
Here is a solution with just three simple scans. No CTEs, no recursion, no joins, no table updates in a loop, no "group by" — as a result, this solution should scale the best (I think). I think number of scans can be reduced to two, if min and max dates are known in advance; the logic itself just needs two scans — find gaps, applied twice.
declare @datefrom datetime, @datethru datetime
DECLARE @T TABLE (d1 DATETIME, d2 DATETIME)
INSERT INTO @T (d1, d2)
SELECT '2010-01-01','2010-03-31'
UNION SELECT '2010-03-01','2010-06-13'
UNION SELECT '2010-04-01','2010-05-31'
UNION SELECT '2010-06-15','2010-06-25'
UNION SELECT '2010-06-26','2010-07-10'
UNION SELECT '2010-08-01','2010-08-05'
UNION SELECT '2010-08-01','2010-08-09'
UNION SELECT '2010-08-02','2010-08-07'
UNION SELECT '2010-08-08','2010-08-08'
UNION SELECT '2010-08-09','2010-08-12'
UNION SELECT '2010-07-04','2010-08-16'
UNION SELECT '2010-11-01','2010-12-31'
select @datefrom = min(d1) - 1, @datethru = max(d2) + 1 from @t
SELECT
StartDate, EndDate
FROM
(
SELECT
MAX(EndDate) OVER (ORDER BY StartDate) + 1 StartDate,
LEAD(StartDate ) OVER (ORDER BY StartDate) - 1 EndDate
FROM
(
SELECT
StartDate, EndDate
FROM
(
SELECT
MAX(EndDate) OVER (ORDER BY StartDate) + 1 StartDate,
LEAD(StartDate) OVER (ORDER BY StartDate) - 1 EndDate
FROM
(
SELECT d1 StartDate, d2 EndDate from @T
UNION ALL
SELECT @datefrom StartDate, @datefrom EndDate
UNION ALL
SELECT @datethru StartDate, @datethru EndDate
) T
) T
WHERE StartDate <= EndDate
UNION ALL
SELECT @datefrom StartDate, @datefrom EndDate
UNION ALL
SELECT @datethru StartDate, @datethru EndDate
) T
) T
WHERE StartDate <= EndDate
The result is:
StartDate EndDate
2010-01-01 2010-06-13
2010-06-15 2010-08-16
2010-11-01 2010-12-31