Sort two arrays the same way

Question

For example, if I have these arrays:

var name = [\"Bob\",\"Tom\",\"Larry\"];
var age =  [\"10\", \"20\", \"30\"];

And I use name.sort

Answer 1

inspired from @jwatts1980's answer, and @Alexander's answer here I merged both answer's into a quick and dirty solution; The main array is the one to be sorted, the rest just follows its indexes

NOTE: Not very efficient for very very large arrays

 /* @sort argument is the array that has the values to sort
   @followers argument is an array of arrays which are all same length of 'sort'
   all will be sorted accordingly
   example:

   sortMutipleArrays(
         [0, 6, 7, 8, 3, 4, 9], 
         [ ["zr", "sx", "sv", "et", "th", "fr", "nn"], 
           ["zero", "six", "seven", "eight", "three", "four", "nine"] 
         ]
   );

  // Will return

  {  
     sorted: [0, 3, 4, 6, 7, 8, 9], 
     followed: [
      ["zr", th, "fr", "sx", "sv", "et", "nn"], 
      ["zero", "three", "four", "six", "seven", "eight", "nine"]
     ]
   }
 */

You probably want to change the method signature/return structure, but that should be easy though. I did it this way because I needed it

var sortMultipleArrays = function (sort, followers) {
  var index = this.getSortedIndex(sort)
    , followed = [];
  followers.unshift(sort);
  followers.forEach(function(arr){
    var _arr = [];
    for(var i = 0; i < arr.length; i++)
      _arr[i] = arr[index[i]];
    followed.push(_arr);
  });
  var result =  {sorted: followed[0]};
  followed.shift();
  result.followed = followed;
  return result;
};

var getSortedIndex = function (arr) {
  var index = [];
  for (var i = 0; i < arr.length; i++) {
    index.push(i);
  }
  index = index.sort((function(arr){
  /* this will sort ints in descending order, change it based on your needs */
    return function (a, b) {return ((arr[a] > arr[b]) ? -1 : ((arr[a] < arr[b]) ? 1 : 0));
    };
  })(arr));
  return index;
};