What is the meaning of having void in the constructor definition?

Question

Given the following code:

#pragma once

class B
{
public:

    B(void)
    {
    }

    ~B(void)
    {
    }
};

I know I can also write this:

Answer 1

A long time ago you did something like this in C (my pre-ISO C is rusty :) ):

void foo(a, b)
   int a, 
   int b
{
}

while C++ was being created the name mangling required the types of the arguments, so for C++ it was changed to:

void foo(int a, int b)
{
}

and this change was brought forward to C.

At this point, I believe to avoid breaking existing C code this:

void foo() 

and this:

void foo(void)

meant two very different things, () means do not check for the argument number or type, and (void) means takes no arguments. For C++ () meaning not to check anything was not going to work so () and (void) mean the same thing in C++.

So, for C++ () and (void) were always the same thing.

At least that is how I remember it... :-)