Integer to bitfield as a list

Question

I\'ve created a method to convert an int to a bitfield (in a list) and it works, but I\'m sure there is more elegant solution- I\'ve just been staring at it for to

Answer 1

I'm doing this for my program where you specify a template to get your values from an int:

def field(template, value):
    sums = [int(v) if v.__class__==str else len(bin(v))-2 for v in template]
    return [(value>> (sum(sums[:i]) if i else 0) )&(~(~0<

how to use
in the template, specify ints relating to your bit-sizes:

field([0b1,0b111,0b1111], 204) #>>> [0, 6, 12]

or you can specify the bit-size of each value needed using strings: (noob friendly)

field(['1','3','4'], 204) #>>> [0, 6, 12]

EDIT: and vice versa: (separate code)

field(['1','3','4'], [0, 6, 12]) #>>> 204
field([0b1,0b111,0b1111], [0,3,9]) #>>> 150

the code:

def field(template, value):
    res = 0
    for t, v in zip(template, value)[::-1]: res = (res << (t.bit_length() if t.__class__ is int else int(t)) )|v
    return res

EDIT2: faster code^