Function pointers casting in C++

Question

I have a void pointer returned by dlsym(), I want to call the function pointed by the void pointer. So I do a type conversion by casting:

void *gptr = dlsym(         


        

Answer 1

This may help you. It prints "Hello".

#include 

void hello()
{
  std::cout << "Hello" << std::endl;
}

int main() {
  typedef void (*fptr)();
  fptr gptr = (fptr) (void *) &hello;
  gptr();
}

OR you can do:

fptr gptr = reinterpret_cast( (void *) &hello);

where &hello is replaced by the dlsym command.