Function pointers casting in C++

Question

I have a void pointer returned by dlsym(), I want to call the function pointed by the void pointer. So I do a type conversion by casting:

void *gptr = dlsym(         


        

Answer 1

This compiles in Visual Studio without using reinterpret cast:

void *ptr;
int (*func)(void) = (int(*)(void))ptr;
int num = func();