Function pointers casting in C++

Question

I have a void pointer returned by dlsym(), I want to call the function pointed by the void pointer. So I do a type conversion by casting:

void *gptr = dlsym(         


        

Answer 1

I found this (a bit ugly) solution. gcc with maximum warning level does not complain. This example calls dlsym() (that returns a void*) and returns the result in a function pointer.

typedef void (*FUNPTR)();

FUNPTR fun_dlsym(void* handle, const char* name) {
    union {
        void* ptr;
        FUNPTR fptr;
    } u;
    u.ptr = dlsym(handle, name);
    return u.fptr;
}