Setting aspect ratio of 3D plot

Question

I am trying to plot a 3D image of the seafloor from the data of a sonar run over a 500m by 40m portion of the seafloor. I am using matplotlib/mplot3d with Axes3D and I want

Answer 1

That how i solved the wasted space problem:

try: 
    self.localPbAspect=self.pbaspect
    zoom_out = (self.localPbAspect[0]+self.localPbAspect[1]+self.localPbAspect[2]) 
except AttributeError: 
    self.localPbAspect=[1,1,1]
    zoom_out = 0 
xmin, xmax = self.get_xlim3d() /  self.localPbAspect[0]
ymin, ymax = self.get_ylim3d() /  self.localPbAspect[1]
zmin, zmax = self.get_zlim3d() /  self.localPbAspect[2]

# transform to uniform world coordinates 0-1.0,0-1.0,0-1.0
worldM = proj3d.world_transformation(xmin, xmax,
                                         ymin, ymax,
                                         zmin, zmax)

# look into the middle of the new coordinates
R = np.array([0.5*self.localPbAspect[0], 0.5*self.localPbAspect[1], 0.5*self.localPbAspect[2]])
xp = R[0] + np.cos(razim) * np.cos(relev) * (self.dist+zoom_out)
yp = R[1] + np.sin(razim) * np.cos(relev) * (self.dist+zoom_out)
zp = R[2] + np.sin(relev) * (self.dist+zoom_out)
E = np.array((xp, yp, zp))