Safe navigation operator (?.) or (!.) and null property paths

Question

In Angular 2 templates safe operator ?. works, but not in component.ts using TypeScript 2.0. Also, safe navigation operator (!.) doesn

Answer 1

Another alternative that uses an external library is _.has() from Lodash.

E.g.

_.has(a, 'b.c')

is equal to

(a && a.b && a.b.c)

EDIT: As noted in the comments, you lose out on Typescript's type inference when using this method. E.g. Assuming that one's objects are properly typed, one would get a compilation error with (a && a.b && a.b.z) if z is not defined as a field of object b. But using _.has(a, 'b.z'), one would not get that error.