Narrowing conversions in C++0x. Is it just me, or does this sound like a breaking change?

Question

C++0x is going to make the following code and similar code ill-formed, because it requires a so-called narrowing conversion of a double to a int<

Answer 1

A practical instance that I have encountered:

float x = 4.2; // an input argument
float a[2] = {x-0.5, x+0.5};

The numeric literal is implicitly double which causes promotion.