You’re given an array of N 64 bit integers. N may be very large. You know that every integer 1..N appears once in the array, except there is one integer mis
long long int len = A.size();
long long int sumOfN = (len * (len+1) ) /2, sumOfNsq = (len * (len +1) *(2*len +1) )/6;
long long int missingNumber1=0, missingNumber2=0;
for(int i=0;i