Converting Action method call to async Action method call

Question

I\'ve this method

public void Execute(Action action)
{
    try
    {
        action();
    }
    finally
    {
    }
}

and I need to convert it

Answer 1

Try this:

public async void ExecuteAsync(Action action)
{
    await Task.Run(action); 
}

Using Task.Run()creates an awaitable by running your action on a different task. And also bear in mind that handling exceptions on "awaitables" does not work as intended.

Better wrap that action() call in a try catch an do Task.Run() on that wrapper.