Finding elements not in a list

Question

So heres my code:

item = [0,1,2,3,4,5,6,7,8,9]
z = []  # list of integers

for item in z:
    if item not in z:
        print item

z<

Answer 1

No, z is undefined. item contains a list of integers.

I think what you're trying to do is this:

#z defined elsewhere
item = [0, 1, 2, 3, 4, 5, 6, 7, 8, 9]

for i in item:
  if i not in z: print i

As has been stated in other answers, you may want to try using sets.