How do you initialise a dynamic array in C++?

Question

How do I achieve the dynamic equivalent of this static array initialisation:

char c[2] = {};  // Sets all members to \'\\0\';

In other word

Answer 1

The array form of new-expression accepts only one form of initializer: an empty (). This, BTW, has the same effect as the empty {} in your non-dynamic initialization.

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The above applies to pre-C++11 language. Starting from C++11 one can use uniform initialization syntax with array new-expressions

char* c = new char[length]{};
char* d = new char[length]{ 'a', 'b', 'c' };