How to pass array as an argument to a function in Bash

Question

As we know, in bash programming the way to pass arguments is $1, ..., $N. However, I found it not easy to pass an array as an argument to a functio

Answer 1

You could pass the "scalar" value first. That would simplify things:

f(){
  b=$1
  shift
  a=("$@")

  for i in "${a[@]}"
  do
    echo $i
  done
  ....
}

a=("jfaldsj jflajds" "LAST")
b=NOEFLDJF

f "$b" "${a[@]}"

At this point, you might as well use the array-ish positional params directly

f(){
  b=$1
  shift

  for i in "$@"   # or simply "for i; do"
  do
    echo $i
  done
  ....
}

f "$b" "${a[@]}"