I\'ve been trying to round long float numbers like:
32.268907563;
32.268907563;
31.2396694215;
33.6206896552;
...
With no success so far. I
Your solution is calling round without specifying the second argument (number of decimal places)
>>> round(0.44)
0
>>> round(0.64)
1
which is a much better result than
>>> int(round(0.44, 2))
0
>>> int(round(0.64, 2))
0
From the Python documentation at https://docs.python.org/3/library/functions.html#round
round(number[, ndigits])
Return number rounded to ndigits precision after the decimal point. If ndigits is omitted or is None, it returns the nearest integer to its input.
Note
The behavior of round() for floats can be surprising: for example, round(2.675, 2) gives 2.67 instead of the expected 2.68. This is not a bug: it’s a result of the fact that most decimal fractions can’t be represented exactly as a float. See Floating Point Arithmetic: Issues and Limitations for more information.